求函数y=3-x2+2x+3的值域(-x2+2x+3是3的次数)
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求函数y=3-x2+2x+3的值域(-x2+2x+3是3的次数)
求函数y=3-x2+2x+3的值域(-x2+2x+3是3的次数)
求函数y=3-x2+2x+3的值域(-x2+2x+3是3的次数)
y=3^(-x2+2x+3)
=3^[-(x-1)^2+4]
∵-∞<[-(x-1)^2+4]≤4
∴0<3^[-(x-1)^2+4]≤3^4=81
y值域(0,81]