a^2+b^2=1, b^2+c^2=2,c^2+a^2=2,则ab+bc+ca的最小值为( )
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a^2+b^2=1, b^2+c^2=2,c^2+a^2=2,则ab+bc+ca的最小值为( )
a^2+b^2=1, b^2+c^2=2,c^2+a^2=2,则ab+bc+ca的最小值为( )
a^2+b^2=1, b^2+c^2=2,c^2+a^2=2,则ab+bc+ca的最小值为( )
因为(a+b)^2+(b+c)^2+(c+a)^2>=0
即 (a^2+b^2)+( b^2+c^2)+(c^2+a^2)+2( ab+bc+ca)>=0
所以ab+bc+ca>=-0.25