解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=5410x+20y+30z=4112x+20y+28z=4214x+25y+40z=54

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/06 09:54:23
解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=5410x+20y+30z=4112x+20y+28z=4214x+25y+40z=54
xRMKQ+"R|3G7T:cHU$ADD.* Z8gj_C,{ϽpxqQ0Ϗ~p^d1 V) P\guTvMkҴ"Zoo/6Rj()[od=b7m{^5konuɳUV-۵4@ײu]+Gsx!z A FM!)U UMCMa CBPcSWtʸL!+Ky,x!H#NjM+ f)-Eğ|K,BxՏN}E^xL%Xma~r~syo)

解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=5410x+20y+30z=4112x+20y+28z=4214x+25y+40z=54
解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=54
10x+20y+30z=41
12x+20y+28z=42
14x+25y+40z=54

解下列三元一次方程组:10x+20y+30z=41 12x+20y+28z=42 14x+25y+40z=5410x+20y+30z=4112x+20y+28z=4214x+25y+40z=54
稍等

不知道对不对,有点乱
算的挺累的
对不,写的有点乱