(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/30 13:54:02
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32
x)060R&Haghm~O=FqF6IE$/!CAPV" u 5ȢP &K =lx{ӾO+g_\g O;{_]d u!y޲鄾=߽ ϧxsi;n_u MpQ$Iw.r===Ae>0t؃r ]d N\c %X@,]C$ٔm/nGq@

(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32

(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32
2^32 -1 =(2^16+1)(2^16-1)
=(2^16+1)(2^8+1)(2^8-1)
.
=(2^16+1)(2^8+1)(2^4+1)(2^2+1)(2+1)(2-1)
=(2^16+1)(2^8+1)(2^4+1)(2^2+1)(2+1)
所以原式 = -1

先在前面乘以(2-1),然后连续运用平方差公式。
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32
=(2²-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)-2^32
=(2^4-1)(2^4+1)(2^8...

全部展开

先在前面乘以(2-1),然后连续运用平方差公式。
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)-2^32
=(2²-1)(2²+1)(2^4+1)(2^8+1)(2^16+1)-2^32
=(2^4-1)(2^4+1)(2^8+1)(2^16+1)-2^32
=(2^8-1)(2^8+1)(2^16+1)-2^32
=(2^16-1)(2^16+1)-2^32
=2^32-1-2^32
=-1

收起