(x+y)^2-8(x+y)+48=
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(x+y)^2-8(x+y)+48=
(x+y)^2-8(x+y)+48=
(x+y)^2-8(x+y)+48=
使用换元法吧~把(X+Y)看成一个整体来做.
比如设t=(x+y),这样就把(x+y)看成是一个整体了.
即t^2-8t+48,因式分解有:(t+4)(t-12).
把t换回来,有(x+y+4)(x+y-12).
希望可以帮助到你对这类题目的思路.
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