求解三角函数方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y求解方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y,其中x,y,z为已知量,c4,c5的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/20 05:47:41
![求解三角函数方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y求解方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y,其中x,y,z为已知量,c4,c5的值](/uploads/image/z/11647244-20-4.jpg?t=%E6%B1%82%E8%A7%A3%E4%B8%89%E8%A7%92%E5%87%BD%E6%95%B0%E6%96%B9%E7%A8%8B%E7%BB%84-cos%28c4%29sin%28c5%29%3Dcos%28c3%29x%2Bsin%28c3%29z%EF%BC%9Bcos%28c5%29%3D-sin%28c3%29x%2Bcos%28c3%29z%EF%BC%9B+-sin%28c4%29sin%28c5%29%3Dy%E6%B1%82%E8%A7%A3%E6%96%B9%E7%A8%8B%E7%BB%84-cos%28c4%29sin%28c5%29%3Dcos%28c3%29x%2Bsin%28c3%29z%EF%BC%9Bcos%28c5%29%3D-sin%28c3%29x%2Bcos%28c3%29z%EF%BC%9B+-sin%28c4%29sin%28c5%29%3Dy%2C%E5%85%B6%E4%B8%ADx%2Cy%2Cz%E4%B8%BA%E5%B7%B2%E7%9F%A5%E9%87%8F%2Cc4%2Cc5%E7%9A%84%E5%80%BC)
xOOAƿJBҙٿ̟]
1BӒpPhcbօO[N|[rP<RP&NǟMkbiU^(g#.ԗ3a/ʝV_;5]fCc7ypՕҌFc"99i*LSt^X;#AxOuRᦕ:cii87TL^ExwraQؕq9ONzIzf-YK/۰%ok#^!yos>K|NrޭՂ' E\"%-24]tSu͂oZnjl0Cct0sLCˤ$*97
_',0,>RA,>e1,F*Mι2Bh0ڎȒ^V7N
求解三角函数方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y求解方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y,其中x,y,z为已知量,c4,c5的值
求解三角函数方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y
求解方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y,其中x,y,z为已知量,c4,c5的值
求解三角函数方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y求解方程组-cos(c4)sin(c5)=cos(c3)x+sin(c3)z;cos(c5)=-sin(c3)x+cos(c3)z; -sin(c4)sin(c5)=y,其中x,y,z为已知量,c4,c5的值
最后的那个方程应该是-sin(c4)cos(c5)=y 吧,要不在推导中会出现矛盾
推导如图示: