①x-2=2(y-1) ②2(x-2)+(Y-1)=5用整体代入法解方程组
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①x-2=2(y-1) ②2(x-2)+(Y-1)=5用整体代入法解方程组
①x-2=2(y-1) ②2(x-2)+(Y-1)=5用整体代入法解方程组
①x-2=2(y-1) ②2(x-2)+(Y-1)=5用整体代入法解方程组
x-2=2(y-1),①
2(x-2)+(y-1)=5,②
把①代入②,得
2*2(y-1)+(y-1)=5,
所以5(y-1)=5,
所以y-1=1,
所以y=2,
把y=2代入①,得
x=2(y-1)+2=2(2-1)+2=3,
所以x=3,
y=2.
将①代入②得
4(y-1)+y-1=5
所以y-1=1
y=2
x-2=2(y-1)=2
x=4
把(1)代入(2)
2*[2(y-1)]+(y-1)=5
4(y-1)+(y-1)=5
5(y-1)=5
y-1=1
y=2
x-2=2(y-1)=2*1=2
x=4
解析: 方程x-2=2(y-1)可化为:x-2=2y-2,解得x=2y 将x=2y代入方程2(x-2)+(y-1)=5,可得: 2(2y-2)+(y-1)=5 即4y-4+y-1=5 5y=10 解得y=2,x=4