sinA=3sin(2π/3-A) SINA=?sinA=3sin(2π/3-A) SINA=?答案是-3√3cosA
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 13:08:21
xJ@W)$I*A/^ 2UnDA kYe`LbX@|<2ԇ:|=m^כ |_.iv7VǺY2,#s1VIaOFqe1J5mƔ0ػԴ-op*99aIJ)ty!((rsqʤSO$XaV) Ze#HJd",F*OʍD<
aA
Rib
ߖv
sinA=3sin(2π/3-A) SINA=?sinA=3sin(2π/3-A) SINA=?答案是-3√3cosA
sinA=3sin(2π/3-A) SINA=?
sinA=3sin(2π/3-A) SINA=?答案是-3√3cosA
sinA=3sin(2π/3-A) SINA=?sinA=3sin(2π/3-A) SINA=?答案是-3√3cosA
1- sin(2π/3 - a)/sina
sinA=3sin(2π/3-A) SINA=?sinA=3sin(2π/3-A) SINA=?答案是-3√3cosA
设锐角三角形ABC的三个内角为,a,b,c分别是内角A,B,C所对边长,并且sinA*sinA=sin(π/3+B)+sin(π/3-B)+sinB*sinB(1) 求角A的值(2) 若向量AB*向量AC=12,a=2√7,求b,c(其中b<c)“sinA*sinA=sin(π/3+B)+si
在三角形ABC中,sinA-sinB/sin(A B)=√2sinA-si在三角形ABC中,sinA-sinB/sin(A B)=√2sinA-sinC/sinA sinB.(1)求B,(2)若cosA=3/5,求sinC的值
设(sina)^2-sina-2(cosa)^2=0,求sin(a-3π/2)
已知(sina+cosa)/(sina-cosa)=3 则2sin'a+(sina-cosa)'=?
证明sinA+sin(A+2π/3)+sin(A-2π/3)=0
证明sinA+sin(A+2π/3)+sin(A-2π/3)=0
若3sin²a+sin²β=2sina,求2sina+sin²β
sinA+sin(120-A)=3/2 求A度数
sin(a+kπ)=2cos[a+(k+1)π].求5cosa+3sina/4sina-2cosa
sin(a+kπ)=2cos[a+(k+1)π].求5cosa+3sina/4sina-2cosa
sin(6/π-a)=1/3 sina=
已知sin(π+a)=1/3,则sina=
sin(3π-a)=sina?三角函数诱导
已知3SIN^2A+2SIN^2B=5SINA,求SIN^2A+SIN^2B范围
已知sina=15/17,a∈(π/2,π),求sin(π/3+a),sin(π/3-a)
已知sina=15/17,a∈(π/2,π)求sin(π/3+a),sin(π/3-a)急