1:解方程:x+y+z=180x+y=100z=2y2;已知等腰三角形两边的和与差为12和6,求等腰三角形的周长.3:已知D是△ABC内一点,我们会得到∠ADB=∠DAC+∠DBC+∠C这一结论,请说明理由.4:在△ABC中,∠A=70°,高BE,C
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![1:解方程:x+y+z=180x+y=100z=2y2;已知等腰三角形两边的和与差为12和6,求等腰三角形的周长.3:已知D是△ABC内一点,我们会得到∠ADB=∠DAC+∠DBC+∠C这一结论,请说明理由.4:在△ABC中,∠A=70°,高BE,C](/uploads/image/z/11668752-0-2.jpg?t=1%EF%BC%9A%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9Ax%2By%2Bz%3D180x%2By%3D100z%3D2y2%EF%BC%9B%E5%B7%B2%E7%9F%A5%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%E4%B8%A4%E8%BE%B9%E7%9A%84%E5%92%8C%E4%B8%8E%E5%B7%AE%E4%B8%BA12%E5%92%8C6%2C%E6%B1%82%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2%E7%9A%84%E5%91%A8%E9%95%BF.3%EF%BC%9A%E5%B7%B2%E7%9F%A5D%E6%98%AF%E2%96%B3ABC%E5%86%85%E4%B8%80%E7%82%B9%2C%E6%88%91%E4%BB%AC%E4%BC%9A%E5%BE%97%E5%88%B0%E2%88%A0ADB%3D%E2%88%A0DAC%2B%E2%88%A0DBC%2B%E2%88%A0C%E8%BF%99%E4%B8%80%E7%BB%93%E8%AE%BA%2C%E8%AF%B7%E8%AF%B4%E6%98%8E%E7%90%86%E7%94%B1.4%EF%BC%9A%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0A%3D70%C2%B0%2C%E9%AB%98BE%2CC)
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