已知|a-b-1|+|b-1|=0,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+...+1/(a+2012)(b+2012)的值
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![已知|a-b-1|+|b-1|=0,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+...+1/(a+2012)(b+2012)的值](/uploads/image/z/11672754-42-4.jpg?t=%E5%B7%B2%E7%9F%A5%7Ca-b-1%7C%2B%7Cb-1%7C%3D0%2C%E6%B1%821%2Fab%2B1%2F%EF%BC%88a%2B1%EF%BC%89%EF%BC%88b%2B1%EF%BC%89%2B1%2F%EF%BC%88a%2B2%29%EF%BC%88b%2B2%29%2B...%2B1%2F%EF%BC%88a%2B2012%EF%BC%89%EF%BC%88b%2B2012%EF%BC%89%E7%9A%84%E5%80%BC)
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