(x+y-z)(x-y+z)运用公式解决

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(x+y-z)(x-y+z)运用公式解决
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(x+y-z)(x-y+z)运用公式解决
(x+y-z)(x-y+z)运用公式解决

(x+y-z)(x-y+z)运用公式解决

原式=(x+(y-z))*(x-(y-z))=x²-(y-z)²=x²-y²+2yz-z²
满意望采纳~

(x+y-z)(x-y+z)
=[x+(y-z)][x-(y-z)]
=x^2-(y-z)^2
=x^2-(y^2-2yz+z^2)
=x^2-y^2-z^2+2yz

(x+y-z)(x-y+z)
=[x+(y-z)][x-(y-z)]
=x^2-(y-z)^2 平方差公式
=x^2-(y^2-2yz+z^2)完全平方公式
=x^2-y^2+2yz-z^2

  (x+y-z)(x-y+z)=x^2-(y-z)^2=x^2-y^2+2yz-z^2

=x2-xy+xz+xy-y2+yz-xz+yz-z2
=x2-y2-z2+2yz
=x2-(y-z)2

(x+y-z)(x-y+z)
=[x+(y-z)][x-(y-z)]
=x^2-(y-z)^2 平方差公式
=x^2-(y^2-2yz+z^2)完全平方公式
=x^2-y^2+2yz-z^2 有不会的还可以问我