用因式分解法解下列方程 1. x(x-1/2)=x 2. 1/2(x-2)^2+x-2=0 3. 9(2x+3)^2-4(2x-5)^2=0
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![用因式分解法解下列方程 1. x(x-1/2)=x 2. 1/2(x-2)^2+x-2=0 3. 9(2x+3)^2-4(2x-5)^2=0](/uploads/image/z/1169431-7-1.jpg?t=%E7%94%A8%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%E6%B3%95%E8%A7%A3%E4%B8%8B%E5%88%97%E6%96%B9%E7%A8%8B+1.+x%28x-1%2F2%29%3Dx+2.+1%2F2%28x-2%29%5E2%2Bx-2%3D0+3.+9%282x%2B3%29%5E2-4%282x-5%29%5E2%3D0)
用因式分解法解下列方程 1. x(x-1/2)=x 2. 1/2(x-2)^2+x-2=0 3. 9(2x+3)^2-4(2x-5)^2=0
用因式分解法解下列方程 1. x(x-1/2)=x 2. 1/2(x-2)^2+x-2=0 3. 9(2x+3)^2-4(2x-5)^2=0
用因式分解法解下列方程 1. x(x-1/2)=x 2. 1/2(x-2)^2+x-2=0 3. 9(2x+3)^2-4(2x-5)^2=0
1.x(x-1/2)=x
x(x-1/2)-x=0
x(x-1/2-1)=0
x(x-3/2)=0
x=0或x=3/2
2.1/2(x-2)^2+x-2=0
1/2(x-2)(x-2+2)=0
1/2x(x-2)=0
x=0或x=2
3.9(2x+3)^2-4(2x-5)^2=0
[3(2x+3)+2(2x-5)][3(2x+3)-2(2x-5)]=0
(10x-1)(2x+19)=0
x=1/10或x=-19/2
x(x-1/2)=x
x(x-1/2)-x=0
x(x-1/2-1)=0
x=0
x=3/2
1/2(x-2)^2+x-2=0
(x-2)【1/2(x_2)+1)】=0
9(2x+3)^2-4(2x-5)^2=0
【3((2x+3)-2(2x-5)】[3(2x+3)+2(2x-5)]=0
1.x(x-1/2)=x
x(x-1/2)-x=0
x(x-1/2-1)=0
x=0 or x=3/2
2.1/2(x-2)^2+x-2=0
(x-2)^2+2(x-2)=0
(x-2)(x-2+2)=0
x=2 or x=0
3. 9(2x+3)^2-4(2x-5)^2=0
[3(2x+3)-2(2x-5)] [3(2x+3)+2(2x-5)] =0
(6x+9-4x+10) (6x+9+4x-10) =0
(2x+19) (10x-1) =0
x=-19/2 or x=1/10