关于三角形中位线在△ABC中,AD为BC边上的中线,G为AD上一点,且GD=1/2AG,BG交AC于点E,CG交AB于点F.求证:E、F分别AC、AB的中点如图
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![关于三角形中位线在△ABC中,AD为BC边上的中线,G为AD上一点,且GD=1/2AG,BG交AC于点E,CG交AB于点F.求证:E、F分别AC、AB的中点如图](/uploads/image/z/11694684-12-4.jpg?t=%E5%85%B3%E4%BA%8E%E4%B8%89%E8%A7%92%E5%BD%A2%E4%B8%AD%E4%BD%8D%E7%BA%BF%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAD%E4%B8%BABC%E8%BE%B9%E4%B8%8A%E7%9A%84%E4%B8%AD%E7%BA%BF%2CG%E4%B8%BAAD%E4%B8%8A%E4%B8%80%E7%82%B9%2C%E4%B8%94GD%3D1%2F2AG%2CBG%E4%BA%A4AC%E4%BA%8E%E7%82%B9E%2CCG%E4%BA%A4AB%E4%BA%8E%E7%82%B9F.%E6%B1%82%E8%AF%81%EF%BC%9AE%E3%80%81F%E5%88%86%E5%88%ABAC%E3%80%81AB%E7%9A%84%E4%B8%AD%E7%82%B9%E5%A6%82%E5%9B%BE)
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