英语翻译LED must be current limited 100MA MAX which will result in a forward voltage drop of 1.1-1.7VDC.Do not exceed use 39 OHM resistor in series with LED and 5V input or obtain value by R=(Vcc-1.4V)/.10A

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 11:50:07
英语翻译LED must be current limited 100MA MAX which will result in a forward voltage drop of 1.1-1.7VDC.Do not exceed use 39 OHM resistor in series with LED and 5V input or obtain value by R=(Vcc-1.4V)/.10A
xTKOa+;MT$JLjbI5M\LE+ lw`%`K|a}Ѷ1oV;7Ms9𸙻4˥Vnן?hDYQI2 ~Ysxxz'^;O@$1 BҢGQ,=DI09t SCS! d_{E0F#"<Ϧ-DISDbr Ge$4+{yQf̓>ĨrOg%-[C{En̥#cKoBK

英语翻译LED must be current limited 100MA MAX which will result in a forward voltage drop of 1.1-1.7VDC.Do not exceed use 39 OHM resistor in series with LED and 5V input or obtain value by R=(Vcc-1.4V)/.10A
英语翻译
LED must be current limited 100MA MAX which will result in a forward voltage drop of 1.1-1.7VDC.
Do not exceed
use 39 OHM resistor in series with LED and 5V input or obtain value by R=(Vcc-1.4V)/.10A

英语翻译LED must be current limited 100MA MAX which will result in a forward voltage drop of 1.1-1.7VDC.Do not exceed use 39 OHM resistor in series with LED and 5V input or obtain value by R=(Vcc-1.4V)/.10A
流经LED(通常是能发光的光电二级管的意思,由电能激发光子而成)的(正偏)最大电流是100毫安,这个最大电流会在LED管上产生一个1.1V到1.7V左右的正偏电压.
请不要在LED上加载超过100毫安的正偏电流.
将一个39欧姆的电阻与这个LED串联,并以一个5v的电压源作为这个电路的串联输入;可以自己计算与LED串联的电阻的阻值:
R =(Vcc-1.4V)/.10A
其中,那个1.4V就是LED有正偏电流流过时的正偏电压.

LED(发光二极管)的电流必须限制在最大100毫安,此时将产生1.1-1.7V的直流正向压降.
请勿超出!
使用39欧姆的电阻与LED串联以及5V输入,或通过下式取得电阻值R=(Vcc-1.4V)/.10A

率领必须电流限制100最大值而这将产生一个正向电压下降了1.1 1.7vdc 。
不超过!
使用39欧姆的电阻串联LED和5V的输入或获得价值由R = ( VCC的- 1.4 V ) / .10 1