已知f(x)=2sin(2x+π/6)+3,题如下已知f(x)=2sin(2x+π/6)+3,在△ABC中,a,b,c分别是角A,B,C的对边,若f(A)=4,b=1,△ABC的面积为√3/2,求a由f(A)=4得sin(2A+π/6)=0.5,又∵A为三角形内角,∴π/6<2A+π/6<13π/6∴2A+π/6=5π
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