设函数f(x)=x^3-3ax^2+3bx的图像与直线12x+y-1=0相切于点(1,-11),求a.b的值?
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 00:13:45
![设函数f(x)=x^3-3ax^2+3bx的图像与直线12x+y-1=0相切于点(1,-11),求a.b的值?](/uploads/image/z/11924636-68-6.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dx%5E3-3ax%5E2%2B3bx%E7%9A%84%E5%9B%BE%E5%83%8F%E4%B8%8E%E7%9B%B4%E7%BA%BF12x%2By-1%3D0%E7%9B%B8%E5%88%87%E4%BA%8E%E7%82%B9%EF%BC%881%2C-11%EF%BC%89%2C%E6%B1%82a.b%E7%9A%84%E5%80%BC%3F)
x@_N8lb⛘,!^4A-OJ8|vWpgnf}3sqeV?3g6gb@ b`'n*\NEowE $:&@T!x87~
\3Ip"ϙ7~)Z
F8R3Pqw@Z)V5*%H_` ]Pu2۠
设函数f(x)=x^3-3ax^2+3bx的图像与直线12x+y-1=0相切于点(1,-11),求a.b的值?
设函数f(x)=x^3-3ax^2+3bx的图像与直线12x+y-1=0相切于点(1,-11),求a.b的值?
设函数f(x)=x^3-3ax^2+3bx的图像与直线12x+y-1=0相切于点(1,-11),求a.b的值?
求导得f'(x)=3x-6ax+3b 切线斜率是-12 所以f'(1)=-12 3-6a+3b=-12 (1) 切点在函数上 f(1)=-11 1-3a+3b=-11 (1) a=1,b=-3
(x-3)(2x-1)设函数f(x)=ax^³+b,已知f(1)=0,则
急设函数f(x)=2{x}^{3}+ax-2,已知f(x)
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0
已知函数f(x)=x^3-3ax+b(a,b∈R) .(2)设b=0,且g(x)=|f(x)|,(|x|≤1),求函数g(x)的最大值h(a)
设函数f(x)=x^3+ax^2-9x-1(a
设函数f(x)=x^3+ax^2-9x-1(a
设函数f(x)=x^3+ax^2-9x-1(a
设函数f(x)=x^3+ax^2-9x-1(a
设函数 f(x)=x的3次方-3ax+b(a不等于0)求函数f(x)的单调区间与极值点
1、设f(x)=x²+ax+b,A={x|f(x)=x}={a},求a、b的值.2、已知函数f(x)=(px²+2)/(q-3x),f(-x)=-f(x),且f(2)=-5/3,求函数f(x)的解析式.
设函数f(x)=ax(3x上面)+bx(2在x上面)+x在x=1处取得极大值5.求常数a和b.求函数f(x)的极小值设函数f(x)=ax(3在x上面)+bx(2在x上面)+x在x=1处取得极大值5.求常数a和b.求函数f(x)的极
设函数f(x)=x的3次方+ax的2次方-9x-1,(a
设f(x)=x^3+ax^2+bx+1的导数f'(x)满足f'(1)=2a,f'(2)=-b,其中常数a,b属于R(1)求曲线y=f(x)在点(1,f(1))处的切线方程;(2)设g(x)=f'(x)e^(-x),求函数g(x)的极值