作业帮关于函数问题,不是很难.f(x1)-f(x2)=(x1)^2-(x2)^2+1/x1-1/x2=(x1+x2)(x1-x2)+(x2-x1)/x1x2=(x1-x2)[x1x2(x1+x2)-1] 中的+(x2-x1)/x1x2怎么变成[x1x2(x1+x2)-1]
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![关于函数问题,不是很难.f(x1)-f(x2)=(x1)^2-(x2)^2+1/x1-1/x2=(x1+x2)(x1-x2)+(x2-x1)/x1x2=(x1-x2)[x1x2(x1+x2)-1] 中的+(x2-x1)/x1x2怎么变成[x1x2(x1+x2)-1]](/uploads/image/z/11926925-53-5.jpg?t=%E5%85%B3%E4%BA%8E%E5%87%BD%E6%95%B0%E9%97%AE%E9%A2%98%2C%E4%B8%8D%E6%98%AF%E5%BE%88%E9%9A%BE.f%28x1%29-f%28x2%29%3D%28x1%29%5E2-%28x2%29%5E2%2B1%2Fx1-1%2Fx2%3D%28x1%2Bx2%29%28x1-x2%29%2B%28x2-x1%29%2Fx1x2%3D%28x1-x2%29%5Bx1x2%28x1%2Bx2%29-1%5D+%E4%B8%AD%E7%9A%84%2B%28x2-x1%29%2Fx1x2%E6%80%8E%E4%B9%88%E5%8F%98%E6%88%90%5Bx1x2%28x1%2Bx2%29-1%5D)
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关于函数问题,不是很难.f(x1)-f(x2)=(x1)^2-(x2)^2+1/x1-1/x2=(x1+x2)(x1-x2)+(x2-x1)/x1x2=(x1-x2)[x1x2(x1+x2)-1] 中的+(x2-x1)/x1x2怎么变成[x1x2(x1+x2)-1]
关于函数问题,不是很难.
f(x1)-f(x2)=(x1)^2-(x2)^2+1/x1-1/x2=(x1+x2)(x1-x2)+(x2-x1)/x1x2=(x1-x2)[x1x2(x1+x2)-1] 中的+(x2-x1)/x1x2怎么变成[x1x2(x1+x2)-1]
关于函数问题,不是很难.f(x1)-f(x2)=(x1)^2-(x2)^2+1/x1-1/x2=(x1+x2)(x1-x2)+(x2-x1)/x1x2=(x1-x2)[x1x2(x1+x2)-1] 中的+(x2-x1)/x1x2怎么变成[x1x2(x1+x2)-1]
f(x1)-f(x2)
=(x1)^2-(x2)^2+1/x1-1/x2
=(x1+x2)(x1-x2)+(x2-x1)/x1x2
=(x1-x2)[x1x2(x1+x2)-1]
中的+(x2-x1)/x1x2怎么变成[x1x2(x1+x2)-1]
=(x1+x2)(x1-x2)+(x2-x1)/x1x2
=(x1+x2)(x1-x2)-(x1-x2)/x1x2
=(x1-x2)(x1+x2-1/x1x2)
不是x1x2(x1+x2)-1