直线L1的解析式为y=-3x+3,且L1与x轴交于点D,直线L2经过点A,B,直线L1,L2交于点C1)求点D 的坐标(2)求直线L2的函数解析式(3)求△ADC的面积(4)在直线L2上存在于点C的另一点P,使得△ADP与△的面
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![直线L1的解析式为y=-3x+3,且L1与x轴交于点D,直线L2经过点A,B,直线L1,L2交于点C1)求点D 的坐标(2)求直线L2的函数解析式(3)求△ADC的面积(4)在直线L2上存在于点C的另一点P,使得△ADP与△的面](/uploads/image/z/11953726-70-6.jpg?t=%E7%9B%B4%E7%BA%BFL1%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%E4%B8%BAy%3D-3x%2B3%2C%E4%B8%94L1%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%BA%8E%E7%82%B9D%2C%E7%9B%B4%E7%BA%BFL2%E7%BB%8F%E8%BF%87%E7%82%B9A%2CB%2C%E7%9B%B4%E7%BA%BFL1%2CL2%E4%BA%A4%E4%BA%8E%E7%82%B9C1%EF%BC%89%E6%B1%82%E7%82%B9D+%E7%9A%84%E5%9D%90%E6%A0%87%EF%BC%882%EF%BC%89%E6%B1%82%E7%9B%B4%E7%BA%BFL2%E7%9A%84%E5%87%BD%E6%95%B0%E8%A7%A3%E6%9E%90%E5%BC%8F%EF%BC%883%EF%BC%89%E6%B1%82%E2%96%B3ADC%E7%9A%84%E9%9D%A2%E7%A7%AF%EF%BC%884%EF%BC%89%E5%9C%A8%E7%9B%B4%E7%BA%BFL2%E4%B8%8A%E5%AD%98%E5%9C%A8%E4%BA%8E%E7%82%B9C%E7%9A%84%E5%8F%A6%E4%B8%80%E7%82%B9P%2C%E4%BD%BF%E5%BE%97%E2%96%B3ADP%E4%B8%8E%E2%96%B3%E7%9A%84%E9%9D%A2)
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