判断下列两圆的位置关系①(x+2)²+(y-2)²=1与(x-2)²+(y-5)²=16②x²+y²+6x-7=0与x²+y²+6y-27=0
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![判断下列两圆的位置关系①(x+2)²+(y-2)²=1与(x-2)²+(y-5)²=16②x²+y²+6x-7=0与x²+y²+6y-27=0](/uploads/image/z/11960224-16-4.jpg?t=%E5%88%A4%E6%96%AD%E4%B8%8B%E5%88%97%E4%B8%A4%E5%9C%86%E7%9A%84%E4%BD%8D%E7%BD%AE%E5%85%B3%E7%B3%BB%E2%91%A0%28x%2B2%29%26%23178%3B%2B%28y-2%29%26%23178%3B%3D1%E4%B8%8E%28x-2%29%26%23178%3B%2B%28y-5%29%26%23178%3B%3D16%E2%91%A1x%26%23178%3B%2By%26%23178%3B%2B6x-7%3D0%E4%B8%8Ex%26%23178%3B%2By%26%23178%3B%2B6y-27%3D0)
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判断下列两圆的位置关系①(x+2)²+(y-2)²=1与(x-2)²+(y-5)²=16②x²+y²+6x-7=0与x²+y²+6y-27=0
判断下列两圆的位置关系
①(x+2)²+(y-2)²=1与(x-2)²+(y-5)²=16
②x²+y²+6x-7=0与x²+y²+6y-27=0
判断下列两圆的位置关系①(x+2)²+(y-2)²=1与(x-2)²+(y-5)²=16②x²+y²+6x-7=0与x²+y²+6y-27=0
(1) 圆心(-2,2),半径=1
圆心(2,5),半径=4
距离=√[(-2-2)方+(2-5)方]=√25=5=1+4
所以
相外切;
(2) (x+3)方+y方=16
圆心(-3,0),半径=4
x方+(y+3)方=36
圆心(0,-3),半径=6
距离=√(-3-0)方+(0+3)方=3√26-4=2
所以
两圆相交.