已知(x+my)(x+ny)=xˆ2+2xy-6yˆ2,求-(m+n) ×mn的值要
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已知(x+my)(x+ny)=xˆ2+2xy-6yˆ2,求-(m+n) ×mn的值要
已知(x+my)(x+ny)=xˆ2+2xy-6yˆ2,求-(m+n) ×mn的值
要
已知(x+my)(x+ny)=xˆ2+2xy-6yˆ2,求-(m+n) ×mn的值要
=12
(x+my)(x+ny)=x^2+2xy-6y^2
x^2+(m+n)xy+mny^2=x^2+2xy-6y^2
m+n=2,mn=-6
-(m+n)xmn=-2x-6=12