(y+2)(y-2)--(y-1)(y+5)123的2次方减去122乘124(2x +y+z)(2x-y-z)(x+1)(x+3)-(x-2)的2次方 +(x+2)(x-2) (a+2b-1)(-2+ab)(2+ab)
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 23:02:08
![(y+2)(y-2)--(y-1)(y+5)123的2次方减去122乘124(2x +y+z)(2x-y-z)(x+1)(x+3)-(x-2)的2次方 +(x+2)(x-2) (a+2b-1)(-2+ab)(2+ab)](/uploads/image/z/12053449-1-9.jpg?t=%28y%2B2%29%28y-2%29--%28y-1%29%28y%2B5%29123%E7%9A%842%E6%AC%A1%E6%96%B9%E5%87%8F%E5%8E%BB122%E4%B9%98124%EF%BC%882x+%2By%2Bz%29%282x-y-z%29%28x%2B1%29%28x%2B3%29-%28x-2%29%E7%9A%842%E6%AC%A1%E6%96%B9+%2B%EF%BC%88x%2B2%29%28x-2%29+%28a%2B2b-1%29%28-2%2Bab%29%282%2Bab%29)
(y+2)(y-2)--(y-1)(y+5)123的2次方减去122乘124(2x +y+z)(2x-y-z)(x+1)(x+3)-(x-2)的2次方 +(x+2)(x-2) (a+2b-1)(-2+ab)(2+ab)
(y+2)(y-2)--(y-1)(y+5)
123的2次方减去122乘124
(2x +y+z)(2x-y-z)
(x+1)(x+3)-(x-2)的2次方 +(x+2)(x-2)
(a+2b-1)
(-2+ab)(2+ab)
(y+2)(y-2)--(y-1)(y+5)123的2次方减去122乘124(2x +y+z)(2x-y-z)(x+1)(x+3)-(x-2)的2次方 +(x+2)(x-2) (a+2b-1)(-2+ab)(2+ab)
解(1)(y+2)(y-2)--(y-1)(y+5)
=y²-4 -y²-4y+5 = 1-4y
(2)123的2次方减去122乘124
=123²-(123-1)(123+1) = 123² -123²+1 = 1
(3)2x +y+z)(2x-y-z)
=4x²-(y+z)² = 4x²-y²-z²-2yz
(4)(x+1)(x+3)-(x-2)的2次方 +(x+2)(x-2)
=x²+ 4x +3 -x²+4x-4+x²-4 = x²+8x -5
(5﹚
(6)(-2+ab)(2+ab)
=a²b²- 4
(1)原式=y^2-4 -y^2-4y+5 = 1-4y
(2)原式=123^2-(123-1)(123+1) = 123^2 -123^2+1 = 1
(3)原式=4x^2-(y+z)^2 = 4x^2-y^2-z^2-2yz
(4)原式=x^2 + 4x +3 -x^2+4x-4+x^2-4 = x^2 +8x -5
(5)原式=a+2b-1
(6)原式=a^2b^2 - 4
(1)原=y^2-4 -y^2-4y+5 = 1-4y
(2)原=123^2-(123-1)(123+1) = 123^2 -123^2+1 = 1
(3)原=4x^2-(y+z)^2 = 4x^2-y^2-z^2-2yz
(4)原=x^2 + 4x +3 -x^2+4x-4+x^2-4 = x^2 +8x -5
(5)原=a+2b-1
(6)原=a^2b^2 - 4