http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg题目在上面(符号有点小请见谅).
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/08 21:22:44
![http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg题目在上面(符号有点小请见谅).](/uploads/image/z/12056710-22-0.jpg?t=http%3A%2F%2Fhiphotos.baidu.com%2F%25CC%25EC%25C4%25A6%25C2%25DE%2Fpic%2Fitem%2F3076ee158905632c972b430d.jpg%E9%A2%98%E7%9B%AE%E5%9C%A8%E4%B8%8A%E9%9D%A2%EF%BC%88%E7%AC%A6%E5%8F%B7%E6%9C%89%E7%82%B9%E5%B0%8F%E8%AF%B7%E8%A7%81%E8%B0%85%EF%BC%89.)
http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg题目在上面(符号有点小请见谅).
http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg
题目在上面(符号有点小请见谅).
http://hiphotos.baidu.com/%CC%EC%C4%A6%C2%DE/pic/item/3076ee158905632c972b430d.jpg题目在上面(符号有点小请见谅).
[(x^2-2x)/(x^2-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)(x+1)-(2x-1)]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{[x^2-1-2x+1)]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{[x^2-2x]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]*(x+1)/(x^2-2x)*[2x/(x-1)]^2
=[x(x-2)/(x-1)]*1/x(x-2)*[2x/(x-1)]^2
=[1/(x-1)]*[2x/(x-1)]^2
=4x^2/(x-1)^3
(2a/b)^3/[a/(a-b)]-(a/b)/(b/4)
=(2a/b)^3*(a-b)/a-(a/b)*4/b
=8a^3/b^3*(a-b)/a-4a/b^2
=8a^2/b^3*(a-b)-4a/b^2
=8a^2(a-b)/b^3-4a/b^2
=[8a^2(a-b)-4ab]/b^3
=4a[2a(a-b)-b]/b^3
=4a(2a^2-2ab-b)/b^3
[(x^2-2x)/(x^2-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)...
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[(x^2-2x)/(x^2-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{(x-1)-[(2x-1)/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{[x^2-1-2x+1)]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]/{[x^2-2x]/(x+1)]}*[2x/(x-1)]^2
=[x(x-2)/(x+1)(x-1)]*(x+1)/(x^2-2x)*[2x/(x-1)]^2
=[x(x-2)/(x-1)]*1/x(x-2)*[2x/(x-1)]^2
=[1/(x-1)]*[2x/(x-1)]^2
=4x^2/(x-1)^3
(2a/b)^3/[a/(a-b)]-(a/b)/(b/4)
=(2a/b)^3*(a-b)/a-(a/b)*4/b
=8a^3/b^3*(a-b)/a-4a/b^2
=8a^2/b^3*(a-b)-4a/b^2
=8a^2(a-b)/b^3-4a/b^2
=[8a^2(a-b)-4ab]/b^3
=4a[2a(a-b)-b]/b^3
=4a(2a^2-2ab-b)/b^3
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