(1-根号2+根号3)(1-根号2-根号3)
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![(1-根号2+根号3)(1-根号2-根号3)](/uploads/image/z/121237-61-7.jpg?t=%EF%BC%881-%E6%A0%B9%E5%8F%B72%2B%E6%A0%B9%E5%8F%B73%EF%BC%89%EF%BC%881-%E6%A0%B9%E5%8F%B72-%E6%A0%B9%E5%8F%B73%EF%BC%89)
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(1-根号2+根号3)(1-根号2-根号3)
(1-根号2+根号3)(1-根号2-根号3)
(1-根号2+根号3)(1-根号2-根号3)
(1-√2+√3)(1-√2-√3)
=[(1-√2)+√3][(1-√2)-√3]
=(1-√2)²-3
=1-2√2+2-3
=-2√2
(1-根号2)平方-根号3平方
=3-2根号2-3
=-2根号2
(1-√2)²-√3²=1-2√2 2-3=-2√2