如果P在平面区域2x-y+2≥0x-2y+1≤0x+y-2≤0上点Q在曲线x²+(y+2) =1上,那么│PQ│的最小值为()A,(√5)-1B,[4/√(5)]-1C,(2√2)-1D,(√2)-1
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![如果P在平面区域2x-y+2≥0x-2y+1≤0x+y-2≤0上点Q在曲线x²+(y+2) =1上,那么│PQ│的最小值为()A,(√5)-1B,[4/√(5)]-1C,(2√2)-1D,(√2)-1](/uploads/image/z/12146001-33-1.jpg?t=%E5%A6%82%E6%9E%9CP%E5%9C%A8%E5%B9%B3%E9%9D%A2%E5%8C%BA%E5%9F%9F2x-y%2B2%E2%89%A50x-2y%2B1%E2%89%A40x%2By-2%E2%89%A40%E4%B8%8A%E7%82%B9Q%E5%9C%A8%E6%9B%B2%E7%BA%BFx%26sup2%2B%28y%2B2%29%26nbsp%3D1%E4%B8%8A%2C%E9%82%A3%E4%B9%88%E2%94%82PQ%E2%94%82%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BA%EF%BC%88%EF%BC%89A%2C%EF%BC%88%E2%88%9A5%EF%BC%89-1B%2C%5B4%2F%E2%88%9A%285%29%5D-1C%2C%282%E2%88%9A2%29-1D%2C%28%E2%88%9A2%29-1)
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