△ABC内接于圆O,AD⊥BC于D,AO是半径.求证:∠BAD=∠CAO
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△ABC内接于圆O,AD⊥BC于D,AO是半径.求证:∠BAD=∠CAO
△ABC内接于圆O,AD⊥BC于D,AO是半径.求证:∠BAD=∠CAO
△ABC内接于圆O,AD⊥BC于D,AO是半径.求证:∠BAD=∠CAO
延长AO与⊙O交与点E 即AE为直径
连接CE
∵同弧
∴∠ABC=∠AEC
又∵∠ADB=∠ACE=90° 直径所对的圆周角是90°
∴∠BAD=∠CAO
延长AO与圆相交于E点,连接CE,在圆O中角ABC和角AEC共于圆弧AC,由于在圆中同一圆弧的角是相等的,所以∠ABC=∠AEC,又因为∠ADB=∠ACE=90°,所以∠BAD=∠CAO http://zhidao.baidu.com/question/316574232.html 可以参照这个问题 也是我回答的!跟你的问题一样的!