已知y1=x²-x+3,y2=√3(2x-1),当x=?时,y1=y2.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/15 09:13:42
![已知y1=x²-x+3,y2=√3(2x-1),当x=?时,y1=y2.](/uploads/image/z/12385668-12-8.jpg?t=%E5%B7%B2%E7%9F%A5y1%3Dx%26%23178%3B-x%2B3%2Cy2%3D%E2%88%9A3%EF%BC%882x-1%EF%BC%89%2C%E5%BD%93x%3D%3F%E6%97%B6%2Cy1%3Dy2.)
x){}K+
m+Ԕ
-u+u*lu2~èBN{'W?MH&Hlv6LHXы`-vDVR }|˅;jjjVh
5AXF.X:̌J=5x1
!$RaQ ~qAb( 4
已知y1=x²-x+3,y2=√3(2x-1),当x=?时,y1=y2.
已知y1=x²-x+3,y2=√3(2x-1),当x=?时,y1=y2.
已知y1=x²-x+3,y2=√3(2x-1),当x=?时,y1=y2.
y1=x²-x+3,y2=√3(2x-1)
若y1=y2
则x²-x+3=√3(2x-1)
移项:
x²-(1+2√3)x+(√3+1)√3=0
(x-√3)[x-(1+√3)]=0
∴x-√3=0或x-(1+√3)=0
∴当x=√3 ,或x=1+√3时,y1=y2