作业帮关于python里面的set,set之后的集合元素是如何让排列的RT,看下面的例子,>>>set('cheeseshop')set(['c','e','h','o','p','s'])>>>set('shop')set(['h','s','o','p'])>>> set('01234')set(['1', '0', '3', '2', '4'])>>> set('1234')set(['1', '
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/14 16:12:23
![关于python里面的set,set之后的集合元素是如何让排列的RT,看下面的例子,>>>set('cheeseshop')set(['c','e','h','o','p','s'])>>>set('shop')set(['h','s','o','p'])>>> set('01234')set(['1', '0', '3', '2', '4'])>>> set('1234')set(['1', '](/uploads/image/z/12392449-25-9.jpg?t=%E5%85%B3%E4%BA%8Epython%E9%87%8C%E9%9D%A2%E7%9A%84set%2Cset%E4%B9%8B%E5%90%8E%E7%9A%84%E9%9B%86%E5%90%88%E5%85%83%E7%B4%A0%E6%98%AF%E5%A6%82%E4%BD%95%E8%AE%A9%E6%8E%92%E5%88%97%E7%9A%84RT%2C%E7%9C%8B%E4%B8%8B%E9%9D%A2%E7%9A%84%E4%BE%8B%E5%AD%90%2C%3E%3E%3Eset%28%27cheeseshop%27%29set%28%5B%27c%27%2C%27e%27%2C%27h%27%2C%27o%27%2C%27p%27%2C%27s%27%5D%29%3E%3E%3Eset%28%27shop%27%29set%28%5B%27h%27%2C%27s%27%2C%27o%27%2C%27p%27%5D%29%3E%3E%3E+set%28%2701234%27%29set%28%5B%271%27%2C+%270%27%2C+%273%27%2C+%272%27%2C+%274%27%5D%29%3E%3E%3E+set%28%271234%27%29set%28%5B%271%27%2C+%27)
关于python里面的set,set之后的集合元素是如何让排列的RT,看下面的例子,>>>set('cheeseshop')set(['c','e','h','o','p','s'])>>>set('shop')set(['h','s','o','p'])>>> set('01234')set(['1', '0', '3', '2', '4'])>>> set('1234')set(['1', '
关于python里面的set,set之后的集合元素是如何让排列的
RT,看下面的例子,
>>>set('cheeseshop')
set(['c','e','h','o','p','s'])
>>>set('shop')
set(['h','s','o','p'])
>>> set('01234')
set(['1', '0', '3', '2', '4'])
>>> set('1234')
set(['1', '3', '2', '4'])
这个怎么排的啊?
关于python里面的set,set之后的集合元素是如何让排列的RT,看下面的例子,>>>set('cheeseshop')set(['c','e','h','o','p','s'])>>>set('shop')set(['h','s','o','p'])>>> set('01234')set(['1', '0', '3', '2', '4'])>>> set('1234')set(['1', '
set是无序集合,python不保证其中元素的次序.打印结果取决于其内部存储结构和输出方式.
你打个长的就知道了
>>> set('012345678910')
set(['1','0','3','2','5','4','7','6','9','8'])
说明它是按类似二维数组的方式保存的,先把重复的元素剔除,然后把元素按21436587的顺序存进二维数组