[a+b]²-[a+b]³因式分解,
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[a+b]²-[a+b]³因式分解,
[a+b]²-[a+b]³因式分解,
[a+b]²-[a+b]³因式分解,
显然公因式是(a+b)²
所以原式=-(a+b)²[(a+b)-1]
=-(a+b)²(a+b-1)
[a+b]²-[a+b]³
=(a+b)²(1-a-b)