{x+y}/2+{x-y}/3=5 {x+y}/2-{x+y}/3=-1 解二元一次方程 3Q!| {x+y}/2+{x-y}/3=5 | {x+y}/2-{x+y}/3=-1
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{x+y}/2+{x-y}/3=5 {x+y}/2-{x+y}/3=-1 解二元一次方程 3Q!| {x+y}/2+{x-y}/3=5 | {x+y}/2-{x+y}/3=-1
{x+y}/2+{x-y}/3=5 {x+y}/2-{x+y}/3=-1 解二元一次方程 3Q!
| {x+y}/2+{x-y}/3=5
| {x+y}/2-{x+y}/3=-1
{x+y}/2+{x-y}/3=5 {x+y}/2-{x+y}/3=-1 解二元一次方程 3Q!| {x+y}/2+{x-y}/3=5 | {x+y}/2-{x+y}/3=-1
{x+y}/2+{x-y}/3=5 ..(1)
{x+y}/2-{x+y}/3=-1 ..(2)
(1)+(2)得
3{x+y}=-2
x+y=4 ..(3)
将(3)带入(1),得
x-y=9 ..(4)
(3)+(4),得
x=13/2
(3)-(4),得
y=-5/2
x=13/2,y=-5/2
如仍有疑惑,欢迎追问.祝:
你确定题目对么?
给你个建议,将(X+Y)看成A,(X-Y)看成B,先算出A和B
A/2+B/3=5
A/2-A/3=-1,A=-6,B=24
即X+Y=-6,X-Y=24
X=9,Y=-15
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