用js正则匹配1234567890出1234 56 78 90 我写的是var re=/(\d{4})(\d{2})(\d{2})(\d{2})/求一个更简单的写法,
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![用js正则匹配1234567890出1234 56 78 90 我写的是var re=/(\d{4})(\d{2})(\d{2})(\d{2})/求一个更简单的写法,](/uploads/image/z/12409604-44-4.jpg?t=%E7%94%A8js%E6%AD%A3%E5%88%99%E5%8C%B9%E9%85%8D1234567890%E5%87%BA1234+56+78+90+%E6%88%91%E5%86%99%E7%9A%84%E6%98%AFvar+re%3D%2F%EF%BC%88%5Cd%7B4%7D%EF%BC%89%EF%BC%88%5Cd%7B2%7D%EF%BC%89%EF%BC%88%5Cd%7B2%7D%EF%BC%89%EF%BC%88%5Cd%7B2%7D%EF%BC%89%2F%E6%B1%82%E4%B8%80%E4%B8%AA%E6%9B%B4%E7%AE%80%E5%8D%95%E7%9A%84%E5%86%99%E6%B3%95%2C)
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用js正则匹配1234567890出1234 56 78 90 我写的是var re=/(\d{4})(\d{2})(\d{2})(\d{2})/求一个更简单的写法,
用js正则匹配1234567890出1234 56 78 90 我写的是var re=/(\d{4})(\d{2})(\d{2})(\d{2})/
求一个更简单的写法,
用js正则匹配1234567890出1234 56 78 90 我写的是var re=/(\d{4})(\d{2})(\d{2})(\d{2})/求一个更简单的写法,
匹配1234567890输出1234 56 78 90?
alert('1234567890'.replace(/^(\d{4})(\d{2})(\d{2})(\d{2})$/, '$1 $2 $3 $4'));