(√ a²-3a+1)+b²+2b+1=0,则a²+(1/a)-|b|的值为
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(√ a²-3a+1)+b²+2b+1=0,则a²+(1/a)-|b|的值为
(√ a²-3a+1)+b²+2b+1=0,则a²+(1/a)-|b|的值为
(√ a²-3a+1)+b²+2b+1=0,则a²+(1/a)-|b|的值为
前面括号内是开根号的,.就是根号下的a*a-3a+1=0 b*b+2b+1=0
解得a=(3+根号5)/2 或(3-根号5)/2 b =--1
带入最后的式子 有 4--根号5 或 1--3*根号5