数列an满足an+1 - an + an-1=0 (n≥2),且a1=1,a2=-1,则a2011= a.1 b.-1 c.2 d.-2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/02 21:24:34
x){6uӎyv/|msbBb655Px#QR{:u옒hhkhdkcfBBBBMR>/jT.H605 =iÍDmu@\
Ov/3ٓN\l|Ƚk.0eCg~qAb4lG$A Zs
数列an满足an+1 - an + an-1=0 (n≥2),且a1=1,a2=-1,则a2011= a.1 b.-1 c.2 d.-2
数列an满足an+1 - an + an-1=0 (n≥2),且a1=1,a2=-1,则a2011= a.1 b.-1 c.2 d.-2
数列an满足an+1 - an + an-1=0 (n≥2),且a1=1,a2=-1,则a2011= a.1 b.-1 c.2 d.-2
an+1 - an + an-1=0 (n≥2)且a1=1,a2=-1,
an-an-1+an-2=0
相加,得
an+1+an-2=0
an+1=-an-2=an-5
所以
以6为周期
2011÷6=335...1
所以
a2011=a1=1
选a
A
已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an
已知数列{an}中满足(An+1-An)(An+1+An)=16,且a1=1,an
数列{an}满足a1=1 an+1=2n+1an/an+2n
已知数列{an}满足an+1=an+n,a1等于1,则an=?
数列{an}满足a1=1,且an=an-1+3n-2,求an
数列an满足a1=2,an+1=4an+9,则an=?
已知数列{an}满足an+1=2an+3.5^n,a1=6.求an
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
数列an满足a1=2,an+1=an²求an
数列an满足a1=2,an+1=an²求an
数列[An]满足An+1-An+3=0,且A1=-5.求An.
数列{an}满足an=p/(pn+1-p)(0
已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列
已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an
数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an
已知数列{an}满足a1=1,an+1 -an+2an+1•an=0求通项
数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an
已知数列{an}满足a1=1,a2=3,an+2=3an+1-2an求an