若a>0,则a=(√2)²,运用此规律解题,若x=(√3)+1,y=(√3)-1,求()(x+√(xy))/((√xy)+y))+(((√xy)-y)/(x-(√xy))的值
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若a>0,则a=(√2)²,运用此规律解题,若x=(√3)+1,y=(√3)-1,求()(x+√(xy))/((√xy)+y))+(((√xy)-y)/(x-(√xy))的值
若a>0,则a=(√2)²,运用此规律解题,若x=(√3)+1,y=(√3)-1,求()(x+√(xy))/((√xy)+y))+(((√xy)-y)/(x-(√xy))的值
若a>0,则a=(√2)²,运用此规律解题,若x=(√3)+1,y=(√3)-1,求()(x+√(xy))/((√xy)+y))+(((√xy)-y)/(x-(√xy))的值
显然
(x+√xy)/(√xy+y)+ (√xy-y)/ (x-√xy)
=√x /√y + √y /√x
=(x+y) /√xy
而x+y=2√3,xy=2
所以
原式
=2√3 / 2
=√3