a²(b²+c²-a²)=b²(a²+c²-b²)① 问1式是怎么变为2式的?a²(b²-a²+c²)+b²(b²-a²-c²)=0②
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![a²(b²+c²-a²)=b²(a²+c²-b²)① 问1式是怎么变为2式的?a²(b²-a²+c²)+b²(b²-a²-c²)=0②](/uploads/image/z/12486522-66-2.jpg?t=a%26%23178%3B%28b%26%23178%3B%2Bc%26%23178%3B-a%26%23178%3B%29%3Db%26%23178%3B%28a%26%23178%3B%2Bc%26%23178%3B-b%26%23178%3B%29%E2%91%A0+%E9%97%AE1%E5%BC%8F%E6%98%AF%E6%80%8E%E4%B9%88%E5%8F%98%E4%B8%BA2%E5%BC%8F%E7%9A%84%3Fa%26%23178%3B%28b%26%23178%3B-a%26%23178%3B%2Bc%26%23178%3B%29%2Bb%26%23178%3B%28b%26%23178%3B-a%26%23178%3B-c%26%23178%3B%29%3D0%E2%91%A1)
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来源:学生作业帮助网 编辑:作业帮 时间:2024/07/28 19:49:41