3-2(x+1)(x-2)-x^2+3(x+2)(x-3) 其中x=99 先简化再求值(x+1)(x^2+x+1)-(x-1)(x^2-x+1)=(2x+3)(2x-4).求x{(x-1)(y-2)=xy{x(x+2)-4y(y-1)=(x-2y)(x+2y).

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/28 07:47:30
3-2(x+1)(x-2)-x^2+3(x+2)(x-3) 其中x=99 先简化再求值(x+1)(x^2+x+1)-(x-1)(x^2-x+1)=(2x+3)(2x-4).求x{(x-1)(y-2)=xy{x(x+2)-4y(y-1)=(x-2y)(x+2y).
xRJ@4f7(L> E/(Xڃb<( ^jد&46޼μ}$4e;eP>]1_X]# jE< ( @o"=SAM pNp.,*p4UCRkzݡwxloߧaݒيu϶\Yd㶙 6;|YHlŎS &Q<*pFy

3-2(x+1)(x-2)-x^2+3(x+2)(x-3) 其中x=99 先简化再求值(x+1)(x^2+x+1)-(x-1)(x^2-x+1)=(2x+3)(2x-4).求x{(x-1)(y-2)=xy{x(x+2)-4y(y-1)=(x-2y)(x+2y).
3-2(x+1)(x-2)-x^2+3(x+2)(x-3) 其中x=99 先简化再求值
(x+1)(x^2+x+1)-(x-1)(x^2-x+1)=(2x+3)(2x-4).求x
{(x-1)(y-2)=xy
{x(x+2)-4y(y-1)=(x-2y)(x+2y).

3-2(x+1)(x-2)-x^2+3(x+2)(x-3) 其中x=99 先简化再求值(x+1)(x^2+x+1)-(x-1)(x^2-x+1)=(2x+3)(2x-4).求x{(x-1)(y-2)=xy{x(x+2)-4y(y-1)=(x-2y)(x+2y).
第一个=3-2(x^2-x-2)-x^2+3(x^2-x-6)=-x-11其中x=99时,原式=-110
第二个两边分别把括号打开x^3+2x^2+2x+1-x^3+2x^2-2x+1=4x^2-2x-12化简4x^2+2=4x^2-2x-12==>x=-7
第三个括号打开第一式xy-y-2x+2=xy==>2x+y=2
第二式x^2+2x-4y^2+4y=x^2-4y^2==>2x+4y=0
联立解得x=4/3 y=-2/3

f(x)=x/(1+x) x>=0 f1(X)=f(X) fn(X)=fn-1[fn-1(x)]求fn(x)证明:f1(X)+2f2(X)+3f3(x)+……+nfn(X) 解九宫格题目(X为未知数)9 X 2 X 7 X 8 X XX X 4 X X 9 X 6 X1 3 X 5 X X X X 24 X X 8 5 X X 1 XX 8 9 4 X 1 6 7 XX 1 X X 3 6 X X 88 X X X X 2 X 3 6X 5 X 6 X X 9 X XX X 7 X 4 X 2 X 1 请问这道题咋做 :(x)X (x+1) X (x+2) X (x+3) =360 *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x x-3/x²-1 ÷ (x-3)(x+1)/x²+2x+1 + 1/x+1,其中x=2 七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式:X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X. (x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3) (x-1)^3(x+1)(x-2)/(x+4) x(x+1)(x+2)(x+3)+1 (换元法) 计算 x(x+3)-(x-1)(x-2) 化简:x(2x+1)-x(x-3) (x+1)(x+2)(x+3)(x+4)+1(x+1)(x-2)(x+3)(x-4)+25 若|x|=7,若|x|=0 则x= 5-3x²+5x-(2x²-3x) (X²-3x+1)(三分之二x²-5x-3) 计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1 (x-1/x+1 - x+1/x-3 )除 2/x²+2x+1 x(x平方-1)+2X平方(X+1)-3X(2X-5)帮个忙 【(Xˇ2-X)/x】 ·【 x/(X+1)】+【(3x+1)】