作业帮函数y=-cos(x-π/3) ,x∈(2π/3,4π/3)的最大值是函数y=-cos(x-π/3) (x∈[2π/3,4π/3])的最大值是多少 补充一题.已知cos(π+α)=1/2 则sin(π/2-α)的值为
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![函数y=-cos(x-π/3) ,x∈(2π/3,4π/3)的最大值是函数y=-cos(x-π/3) (x∈[2π/3,4π/3])的最大值是多少 补充一题.已知cos(π+α)=1/2 则sin(π/2-α)的值为](/uploads/image/z/12511109-29-9.jpg?t=%E5%87%BD%E6%95%B0y%3D-cos%28x-%CF%80%2F3%29+%2Cx%E2%88%88%282%CF%80%2F3%2C4%CF%80%2F3%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E6%98%AF%E5%87%BD%E6%95%B0y%3D-cos%28x-%CF%80%2F3%29+%28x%E2%88%88%5B2%CF%80%2F3%2C4%CF%80%2F3%5D%29%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E6%98%AF%E5%A4%9A%E5%B0%91+%E8%A1%A5%E5%85%85%E4%B8%80%E9%A2%98.%E5%B7%B2%E7%9F%A5cos%28%CF%80%2B%CE%B1%29%3D1%2F2+%E5%88%99sin%28%CF%80%2F2-%CE%B1%29%E7%9A%84%E5%80%BC%E4%B8%BA)
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函数y=-cos(x-π/3) ,x∈(2π/3,4π/3)的最大值是函数y=-cos(x-π/3) (x∈[2π/3,4π/3])的最大值是多少 补充一题.已知cos(π+α)=1/2 则sin(π/2-α)的值为
函数y=-cos(x-π/3) ,x∈(2π/3,4π/3)的最大值是
函数y=-cos(x-π/3) (x∈[2π/3,4π/3])的最大值是多少
补充一题.已知cos(π+α)=1/2 则sin(π/2-α)的值为
函数y=-cos(x-π/3) ,x∈(2π/3,4π/3)的最大值是函数y=-cos(x-π/3) (x∈[2π/3,4π/3])的最大值是多少 补充一题.已知cos(π+α)=1/2 则sin(π/2-α)的值为
1) x∈[2π/3,4π/3] ==> (x-π/3)∈[π/3,π]
==> 在此区间上余弦函数最大值为 y=cosπ/3=1/2
2) sin(π/2-α)=cosα=-cos(π+α)=-1/2
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