已知/a-4/+√(b-9)=0,计算(a²+ab)/(b²)·(a²-ab)/(a²-b²)
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已知/a-4/+√(b-9)=0,计算(a²+ab)/(b²)·(a²-ab)/(a²-b²)
已知/a-4/+√(b-9)=0,计算(a²+ab)/(b²)·(a²-ab)/(a²-b²)
已知/a-4/+√(b-9)=0,计算(a²+ab)/(b²)·(a²-ab)/(a²-b²)
因为|a-4|+√(b-9)=0,|a-4|≥0,√(b-9)≥0
所以a-4=0且b-9=0
a=4,b=9
所以
(a²+ab)/(b²)×(a²-ab)/(a²-b²)
=[a(a+b)]/(b²)×[a(a-b)]/[(a+b)(a-b)]
=(a²)/(b²)
=(4²)/(9²)
=16/81