若丨2a-1丨+(3b+2)*(3b+2)=0,求a*2+3b*3b/a+的值
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若丨2a-1丨+(3b+2)*(3b+2)=0,求a*2+3b*3b/a+的值
若丨2a-1丨+(3b+2)*(3b+2)=0,求a*2+3b*3b/a+的值
若丨2a-1丨+(3b+2)*(3b+2)=0,求a*2+3b*3b/a+的值
绝对值和平方大于等于0,相加等于0,若有一个大于0,则另一个小于0,不成立.
所以两个都等于0
所以2a-1=0,3b+2=0
a=1/2,b=2/3
后面不完整,你自己算一下吧
由于绝对值与一个数的平方具有非负性所以
2a=1 3b=-2 所以 A*2+3B*3B/A =1+4/0.5=1+8=9
∵丨2a-1丨+(3b+2)×(3b+2)=0
∴丨2a-1丨=0,(3b+2)×(3b+2)=0
2a-1=0,3b=-2,-2÷3=-2/3,b=-2/3
2a=1,1÷2=1/2,a=1/2
2a+3b×3b/a
=2×1/2+【3×-(2/3)】×【3×(-2/3)】/一分之二
=1+(-2)×(-4)
=1+8
=9