(x+1)(x-1)-(x-1)(1-x)=10,求x

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(x+1)(x-1)-(x-1)(1-x)=10,求x
(x+1)(x-1)-(x-1)(1-x)=10,求x

(x+1)(x-1)-(x-1)(1-x)=10,求x
x²-1+x²-2x+1=10
2x²-2x-10=0
x²-x-5=0
x=1/2+√21/2 x=1/2-√21/2

(x+1)(x-1)-(x-1)(1-x)=10
x^2-1+x^2-2x+1=10
2x^2-2x=10
x^2-x-5=0
（x-1/2）^2-21/4=0
当x-1/2=±根号下（21/4）
所以x=（1+根号下21）/2,或x=（1-根号下21）/2

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