=2[1/log3(36)+1/log2(36)] =2[log36(3)+log36(2)]=2[1/log3(36)+1/log2(36)]=2[log36(3)+log36(2)] 这也是换底的一种?

为什么log3(2)=1/log2(3). log2 24-1/log3 2= 已知log3^(a+1)=2 ,则log2^a=? 计算(log3 2)(log2 6-1) log2 1-lg3×log3 2-lg5 log2 1-lg3×log3 2-lg5 log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=? log2(3)+log3(5)+log3(2)=? 解方程：log4{2log3[1+log2(1+3log2 x)]}=1/2 计算(log3(2))*(log2(6-1))=?__________尤其是(log2(6-1))=? (log2 6)×(log3 6)-(log2 3+log3 2)= (log2 6)×(log3 6)-(log2 3+log3 2)= log2(3)*log3(2)=? (log3^2)(log2^3)= log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12= log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9 log5[log3(log2^x)]=1,x= 已知log3 m=-1/log2 3,则m=