如图,在RT△ABC中,∠BAC=90°AB=AC,CE⊥BD交BD的延长线于点E,并且∠1=∠2求证:BD=2CE
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![如图,在RT△ABC中,∠BAC=90°AB=AC,CE⊥BD交BD的延长线于点E,并且∠1=∠2求证:BD=2CE](/uploads/image/z/1254453-69-3.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8RT%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%3D90%C2%B0AB%3DAC%2CCE%E2%8A%A5BD%E4%BA%A4BD%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8E%E7%82%B9E%2C%E5%B9%B6%E4%B8%94%E2%88%A01%3D%E2%88%A02%E6%B1%82%E8%AF%81%EF%BC%9ABD%3D2CE)
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