(9a²+6a+1)分之(a²-4a+4)÷(3a+1)分之(6-3a)
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![(9a²+6a+1)分之(a²-4a+4)÷(3a+1)分之(6-3a)](/uploads/image/z/1255161-57-1.jpg?t=%289a%26%23178%3B%2B6a%2B1%29%E5%88%86%E4%B9%8B%28a%26%23178%3B-4a%2B4%29%C3%B7%283a%2B1%29%E5%88%86%E4%B9%8B%286-3a%29)
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(9a²+6a+1)分之(a²-4a+4)÷(3a+1)分之(6-3a)
(9a²+6a+1)分之(a²-4a+4)÷(3a+1)分之(6-3a)
(9a²+6a+1)分之(a²-4a+4)÷(3a+1)分之(6-3a)
(9a²+6a+1)=(3a+1)²,(a²-4a+4)=(a-2)²,(6-3a)=3(2-a)=-3(a-2).所以(9a²+6a+1)分之(a²-4a+4)÷(3a+1)分之(6-3a)=(3a+1)²分之(a-2)²÷(3a+1)分之-3(a-2)=(3a+1)²分之(a-2)²* -3(a-2)分之(3a+1)=-(9a+3)分之(a-2)