设X,Y都是有理数,且满足方程:2X+根号3乘以Y=-6Y-X/2乘以根号3+20求X与Y的值
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![设X,Y都是有理数,且满足方程:2X+根号3乘以Y=-6Y-X/2乘以根号3+20求X与Y的值](/uploads/image/z/1255718-38-8.jpg?t=%E8%AE%BEX%2CY%E9%83%BD%E6%98%AF%E6%9C%89%E7%90%86%E6%95%B0%2C%E4%B8%94%E6%BB%A1%E8%B6%B3%E6%96%B9%E7%A8%8B%3A2X%2B%E6%A0%B9%E5%8F%B73%E4%B9%98%E4%BB%A5Y%3D-6Y-X%2F2%E4%B9%98%E4%BB%A5%E6%A0%B9%E5%8F%B73%2B20%E6%B1%82X%E4%B8%8EY%E7%9A%84%E5%80%BC)
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设X,Y都是有理数,且满足方程:2X+根号3乘以Y=-6Y-X/2乘以根号3+20求X与Y的值
设X,Y都是有理数,且满足方程:2X+根号3乘以Y=-6Y-X/2乘以根号3+20求X与Y的值
设X,Y都是有理数,且满足方程:2X+根号3乘以Y=-6Y-X/2乘以根号3+20求X与Y的值
条件应该少了,都找不出XY的关系,即使是有理数也~
2x=-6y
根号3y=-x\2*根号3+20
解之得
y=-40
x=120