作业帮∫(cos^3x/sin^2x)dx
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∫(cos^3x/sin^2x)dx
∫(cos^3x/sin^2x)dx
∫(cos^3x/sin^2x)dx
∫(cos^3x/sin^2x)dx
=∫[(1-(sinx)^2]/(sinx)^2dsinx
=∫[1/(sinx)^2-1]dsinx
=-1/sinx-sinx+C
∫(cos^3x/sin^2x)dx
=∫[(cosx)^2/(sinx)^2]*cosxdx
=∫[(1-(sinx)^2]/(sinx)^2dsinx
=∫[1/(sinx)^2-1]dsinx
=-1/sinx-sinx+C
∫sin(x) cos^2(x)dx
∫(cos^3x/sin^2x)dx
∫ [cos^3(x)]/[sin^2 (x)]dx
∫sin^3(x)cos^2(x)dx=
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∫ dx/[sin^(2) x·cos^(2) x]
求不定积分：∫(sin x/cos^3 x)dx
求不定积分：∫(sin x/cos^3 x)dx
∫cos^4x/sin^3x dx=?
∫sin(3x)cos(4x)dx=
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