确定符号:(sinx+tgx)/(cosx+ctgx) (x≠k∏/2,k∈Z)还有一题已知:(tgα)2=2(tgβ)2+1,求证:(sinβ)2=2(sinα)2-1
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![确定符号:(sinx+tgx)/(cosx+ctgx) (x≠k∏/2,k∈Z)还有一题已知:(tgα)2=2(tgβ)2+1,求证:(sinβ)2=2(sinα)2-1](/uploads/image/z/12580938-18-8.jpg?t=%E7%A1%AE%E5%AE%9A%E7%AC%A6%E5%8F%B7%EF%BC%9A%EF%BC%88sinx%2Btgx%EF%BC%89%2F%28cosx%2Bctgx%29+%28x%E2%89%A0k%E2%88%8F%2F2%2Ck%E2%88%88Z%29%E8%BF%98%E6%9C%89%E4%B8%80%E9%A2%98%E5%B7%B2%E7%9F%A5%EF%BC%9A%28tg%CE%B1%292%3D2%28tg%CE%B2%292%2B1%2C%E6%B1%82%E8%AF%81%EF%BC%9A%28sin%CE%B2%292%3D2%28sin%CE%B1%292-1)
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确定符号:(sinx+tgx)/(cosx+ctgx) (x≠k∏/2,k∈Z)还有一题已知:(tgα)2=2(tgβ)2+1,求证:(sinβ)2=2(sinα)2-1
确定符号:(sinx+tgx)/(cosx+ctgx) (x≠k∏/2,k∈Z)
还有一题
已知:(tgα)2=2(tgβ)2+1,求证:(sinβ)2=2(sinα)2-1
确定符号:(sinx+tgx)/(cosx+ctgx) (x≠k∏/2,k∈Z)还有一题已知:(tgα)2=2(tgβ)2+1,求证:(sinβ)2=2(sinα)2-1
使用三角比,代来代去