作业帮化简[(x+2）/（x²-2x)+(x-1)/(x²-4x+4)]除以（x-4)/x
来源：学生作业帮助网 编辑：作业帮 时间：2024/06/10 02:19:40
![化简[(x+2）/（x²-2x)+(x-1)/(x²-4x+4)]除以（x-4)/x](/uploads/image/z/1259215-7-5.jpg?t=%E5%8C%96%E7%AE%80%5B%28x%2B2%EF%BC%89%2F%EF%BC%88x%26%23178%3B-2x%29%2B%28x-1%29%2F%28x%26%23178%3B-4x%2B4%29%5D%E9%99%A4%E4%BB%A5%EF%BC%88x-4%29%2Fx)
x){3h
m{:PS645֨5׀ Thhƾ &6IE0FΆjy`u/x>{Y-;w>oک5Ov<ٱiׂ۟MdǮ@Ɠ [|t tIﳹM` tOmF&q#4"t4٫ d b@44I$q@OES fF B
a$فB {V
化简[(x+2）/（x²-2x)+(x-1)/(x²-4x+4)]除以（x-4)/x
化简[(x+2）/（x²-2x)+(x-1)/(x²-4x+4)]除以（x-4)/x
化简[(x+2）/（x²-2x)+(x-1)/(x²-4x+4)]除以（x-4)/x
根据题目的特点,把第二个加号改为减号.(不然越算越复杂)
原式={(X+2)/［X(X-2)］-(X-1)/(X-2)^2}×X/(X-4)
={(X^2-4-X^2+X)/［X(X-2)^2］×X/(X-4)
=(X-4)X/［X(X-2)^2(X-4)］
=1/(X-2)^2.