函数f(X)=sin(2x-π/4)-2根号2sin^2x的最小值

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函数f(X)=sin(2x-π/4)-2根号2sin^2x的最小值
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函数f(X)=sin(2x-π/4)-2根号2sin^2x的最小值
函数f(X)=sin(2x-π/4)-2根号2sin^2x的最小值

函数f(X)=sin(2x-π/4)-2根号2sin^2x的最小值
f(X)=sin(2x-π/4)-2根号2sin^2x
=√2/2sin2x-√2/2cos2x-√2(1-cos2x)
=√2/2sin2x+√2/2cos2x-√2
=sin(2x+π/4)-√2
当sin(2x+π/4)=-1时,函数有最小值 ymin=-1-√2

T=2π/2=π sin最大是1 所以最大值=1+√2 递增则sin递增所以2kπ-f(x)=1+√2sin(2x-π/4) 由于y=sinxr的周期为2π，故原函数的最小

函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+a) -π 设函数f(x)=sin(2x+ φ)(-π 函数f(x)=sin(2x+&）(-π 函数f(x)=sin(2x+t) (-π 函数f(x)=sin(2x+a）(-π