先化简,再求值,(x²-9)/(x²+6x+9)×(3x³+9x²)/(x²-3x),其中x=-1/3
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/18 03:16:37
![先化简,再求值,(x²-9)/(x²+6x+9)×(3x³+9x²)/(x²-3x),其中x=-1/3](/uploads/image/z/1260230-14-0.jpg?t=%E5%85%88%E5%8C%96%E7%AE%80%2C%E5%86%8D%E6%B1%82%E5%80%BC%2C%28x%26%23178%3B-9%29%2F%28x%26%23178%3B%2B6x%2B9%29%C3%97%283x%26%23179%3B%2B9x%26%23178%3B%29%2F%28x%26%23178%3B-3x%29%2C%E5%85%B6%E4%B8%ADx%3D-1%2F3)
x){gu
:OzmlzڰGGBMZRS6ж<<],`im A5yںɎ6IE4AΆ.tOFF1H= rx1T3XPI1HDq
dTXF 1C i
先化简,再求值,(x²-9)/(x²+6x+9)×(3x³+9x²)/(x²-3x),其中x=-1/3
先化简,再求值,(x²-9)/(x²+6x+9)×(3x³+9x²)/(x²-3x),其中x=-1/3
先化简,再求值,(x²-9)/(x²+6x+9)×(3x³+9x²)/(x²-3x),其中x=-1/3
原式=(x+3)(x-3)/(x+3)²×3x²(x+3)/x(x-3)
=(x-3)/(x+3)×3x(x+3)/(x-3)
=3x
=3×(-1/3)
=-1