若点P在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上若点P=-在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上,点Q在曲线x²+(y+2)²=1,那么|PQ|的最小值为
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![若点P在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上若点P=-在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上,点Q在曲线x²+(y+2)²=1,那么|PQ|的最小值为](/uploads/image/z/1260690-42-0.jpg?t=%E8%8B%A5%E7%82%B9P%E5%9C%A8%E5%B9%B3%E9%9D%A2%E5%8C%BA%E5%9F%9F2x-y%2B2%E2%89%A50%2Cx-2y%2B1%E2%89%A40%2Cx%2By-2%E2%89%A40%E4%B8%8A%E8%8B%A5%E7%82%B9P%3D-%E5%9C%A8%E5%B9%B3%E9%9D%A2%E5%8C%BA%E5%9F%9F2x-y%2B2%E2%89%A50%2Cx-2y%2B1%E2%89%A40%2Cx%2By-2%E2%89%A40%E4%B8%8A%2C%E7%82%B9Q%E5%9C%A8%E6%9B%B2%E7%BA%BFx%26sup2%3B%2B%EF%BC%88y%2B2%29%26sup2%3B%3D1%2C%E9%82%A3%E4%B9%88%7CPQ%7C%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E4%B8%BA)
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若点P在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上若点P=-在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上,点Q在曲线x²+(y+2)²=1,那么|PQ|的最小值为
若点P在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上
若点P=-在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上,点Q在曲线x²+(y+2)²=1,那么|PQ|的最小值为
若点P在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上若点P=-在平面区域2x-y+2≥0,x-2y+1≤0,x+y-2≤0上,点Q在曲线x²+(y+2)²=1,那么|PQ|的最小值为
sqrt(5)-1
【sqrt表示根号】
解法参见附图.