(1)-2x^2+13-15=0 (2)x^2=2√2x-2 (3)(2/3)x^2-(1/6)x=1/2
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![(1)-2x^2+13-15=0 (2)x^2=2√2x-2 (3)(2/3)x^2-(1/6)x=1/2](/uploads/image/z/1261199-47-9.jpg?t=%EF%BC%881%EF%BC%89-2x%5E2%2B13-15%3D0+%282%29x%5E2%3D2%E2%88%9A2x-2+%283%EF%BC%89%282%2F3%29x%5E2-%EF%BC%881%2F6%EF%BC%89x%3D1%2F2)
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(1)-2x^2+13-15=0 (2)x^2=2√2x-2 (3)(2/3)x^2-(1/6)x=1/2
(1)-2x^2+13-15=0 (2)x^2=2√2x-2 (3)(2/3)x^2-(1/6)x=1/2
(1)-2x^2+13-15=0 (2)x^2=2√2x-2 (3)(2/3)x^2-(1/6)x=1/2
(1)-2x^2+13-15=0
(-2x-3)(x+5)=0
x=-3/2 x=-5
(2)x^2=2√2x-2
x^2-2√2x+2=0
(x- √2)^2=0
x= √2
(3)(2/3)x^2-(1/6)x=1/2
4x^2-x-3=0
(4x+3)(x-1)=0
x=-3/4 x=1
因式分解法解下列方程 1、用因式分解法解下列方程:(1)3y^2-5y=0 (2)4x^2=12x (3)x^2+9=-6x (4)9x^2=(x-x^3-3x^2-13x+15 =x^3-3x^2+2x-15x+15 =x(x^2-3x+2)-15(x-1) =x(x-2)(x-1)-15(x-1) =(x-1)[x(x-2)-15] =(x-1)[x^2-2x-15] =(x-1)(x-5)(x+
matlab解数值分析题p=(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)解为1,2,3……,20取多个非常小的数用软件工具求解方程p(x)+n*x^19=0,并
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(x)-2x·x-x-2x+1=0求x的值,
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因式分解:(1)3x^2+7x+2 (2)5x^2+13x-6=0 (3)6x^2+13x-15=0
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(X-3分之x-1-x分之x-4)除以x的平方+3x分之(x+3)(x-2),其中(x-1)(x-2)=0
请问,这十道关于一元一次方程的题目我做对了吗?(1)2X+3X+4X=189X=18X=2(2)13X-15X+X=-3-1X=-3X=3(3)2.5X+10X-6X=15-21.56.5X=6.5X=1(4)4X+3(2X-3))=12-(X+4)4X+6X-9=12X-4810X-12X=-48+9-2X=-57X=28.5(5) 7X+2(3X-3)=207X+6X-6=2013X=20+6
f(x)=(x+1)ln(x+1)+m(x^2+2x) x>=0时,f(x)
(x-2)(x²-6x-9)-x(x²-2x-15),其中x=1/3
MATLAb编程解方程clear;clcsyms xfor n=1:6X2=solve('(x-1)*(x-2)*(x-3)*(x-4)*(x-5)*(x-6)*(x-7)*(x-8)*(x-9)*(x-10)*(x-11)*(x-12)*(x-13)*(x-14)*(x-15)*(x-16)*(x-17)*(x-18)*(x-19)*(x-20)+1e-n*x^19=0',x);double(X2)end与直接代入n=1,2,...6算出来
如果X*X--1=0,那么X*X*X+2*X*X+2008=几?
已知x*x+x-1=0 求x*x*x-2x+11=?
用matlab求解一个优化问题(目标函数非线性,约束函数线性)min f(x)=12*x(1)+21*x(2)+21*x(3)+13*x(4)+20*x(5)+23*x(6)+15*x(7)+17*x(8)+27*x(9)+17*x(10)+19*x(11)+31*x(12)+200*[(x(1)+x(2)+x(3))^0.6+(x(4)+x(5)+x(6))^0.6+(x(7)+x(8)+x(9))
已知x*x+x-1=0求x*x*x-2x+2010的值